How can I turn a string such as "+" into the operator plus?
How about using a lookup dict, but with lambdas instead of operator library.
op = {'+': lambda x, y: x + y,
'-': lambda x, y: x - y}
Then you can do:
print(op['+'](1,2))
And it will output:
3
Use eval() if it is safe (not on servers, etc):
num_1 = 5
num_2 = 10
op = ['+', '-', '*']
result = eval(f'{num_1} {op[0]} {num_2}')
print(result)
Output : 15
I understand that you want to do something like: 5"+"7 where all 3 things would be passed by variables, so example:
import operator
#define operators you wanna use
allowed_operators={
"+": operator.add,
"-": operator.sub,
"*": operator.mul,
"/": operator.truediv}
#sample variables
a=5
b=7
string_operator="+"
#sample calculation => a+b
result=allowed_operators[string_operator](a,b)
print(result)
I was bugged with the same problem, using Jupyter Notebook, I was unable to import the operator module. So the above code helped give me insight but was unable to run on the platform. I figured out a somehwhat primitive way to do so with all the basic funcs and here it is: (This could be heavily refined but it’s a start…)
# Define Calculator and fill with input variables
# This example "will not" run if aplha character is use for num1/num2
def calculate_me():
num1 = input("1st number: ")
oper = input("* OR / OR + OR - : ")
num2 = input("2nd number: ")
add2 = int(num1) + int(num2)
mult2 = int(num1) * int(num2)
divd2 = int(num1) / int(num2)
sub2 = int(num1) - int(num2)
# Comparare operator strings
# If input is correct, evaluate operand variables based on operator
if num1.isdigit() and num2.isdigit():
if oper is not "*" or "/" or "+" or "-":
print("No strings or ints for the operator")
else:
pass
if oper is "*":
print(mult2)
elif oper is "/":
print(divd2)
elif oper is "+":
print(add2)
elif oper is "-":
print(sub2)
else:
return print("Try again")
# Call the function
calculate_me()
print()
calculate_me()
print()