Java: Literal percent sign in printf statement

user_133458 0
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I'm trying to add an actual percent sign into a printf statement in Java and I'm getting the error:

lab1.java:166: illegal escape character
                System.out.printf("%s\t%s\t%1.2f\%\t%1.2f\%\n",ID,pattern,support,confidence);
                                                 ^
lab1.java:166: illegal escape character
                System.out.printf("%s\t%s\t%1.2f\%\t%1.2f\%\n",ID,pattern,support,confidence);
                                                          ^
2 errors

I can't figure out how to put an actual percent sign into my printf? I thought using \% to escape it would work, but it isn't.

Any ideas?

printf escaping java
4 Answers

Check below Code ---

public class Printer {
   public static void main(String[] args) {
      System.out.printf("2 out of 10 is %d%%", 20);
   }
}
user_48239360
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