How to check that an element is in a std::set?

In C++20 we'll finally get std::set::contains method.

#include <iostream>
#include <string>
#include <set>

int main()
{
    std::set<std::string> example = {"Do", "not", "panic", "!!!"};

    if(example.contains("panic")) {
        std::cout << "Found\n";
    } else {
        std::cout << "Not found\n";
    }
}

Since C++20, there is simply (and at last!) bool std::contains(const K&) https://en.cppreference.com/w/cpp/container/set/contains

I use

if(!my_set.count(that_element)) //Element is present...
;

But it is not as efficient as

if(my_set.find(that_element)!=my_set.end()) ....;

My version only saves my time in writing the code. I prefer it this way for competitive coding.

It's this, by a mile.

bool once(uintptr_t val) {
    return visited.emplace(val).second;
}

How could it be otherwise?

https://godbolt.org/z/9zP77jqMc

func5(unsigned long):
        sub     rsp, 24
        mov     QWORD PTR [rsp+8], rdi
        lea     rsi, [rsp+8]
        mov     edi, OFFSET FLAT:visited2
        call    std::pair<std::_Rb_tree_iterator<unsigned long>, bool> std::_Rb_tree<unsigned long, unsigned long, std::_Identity<unsigned long>, std::less<unsigned long>, std::allocator<unsigned long> >::_M_emplace_unique<unsigned long&>(unsigned long&)
        add     rsp, 24
        mov     eax, edx
        ret