How to write an empty indentation block in Python?

Jader_Dias_48465 0
Viewed 28033

The runtime keeps telling me:

expected an indented block

But I don't want write nothing inside my except block, I just want it to catch and swallow the exception.

indentation syntax try-catch python
3 Answers

For those who are very unclear as to why you would want to do this. Here is an example where I initially thought that an empty block would be a good idea:

def set_debug_dir(self, debug_dir=None):
    if debug_dir is None:
        debug_dir = self.__debug_dir
    elif isinstance(debug_dir, (Path, str)):
        debug_dir = debug_dir # this is my null operation
    elif isinstance(debug_dir, list):
        debug_dir = functools.reduce(os.path.join, debug_dir)
    else:
        raise TypeError('Unexpected type for debug_dir: {}'.format(type(debug_dir).__name__))

But it would be more clear to reorganize the statement:

def set_debug_dir(self, debug_dir=None):
    if debug_dir is None:
        debug_dir = self.__debug_dir
    elif isinstance(debug_dir, list):
        debug_dir = functools.reduce(os.path.join, debug_dir)
    elif not isinstance(debug_dir, (Path, str)):
        raise TypeError('Unexpected type for debug_dir: {}'.format(type(debug_dir).__name__))
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