Remove characters except digits from string using Python?

Try:

import re

string = '1abcd2XYZ3'
string_without_letters = re.sub(r'[a-z]', '', string.lower())

this should give:

123

$ python -mtimeit -s'import re;  x="aaa12333bb445bb54b5b52"' 're.sub(r"\D", "", x)'

100000 loops, best of 3: 2.48 usec per loop

$ python -mtimeit -s'import re; x="aaa12333bab445bb54b5b52"' '"".join(re.findall("[a-z]+",x))'

100000 loops, best of 3: 2.02 usec per loop

$ python -mtimeit -s'import re;  x="aaa12333bb445bb54b5b52"' 're.sub(r"\D", "", x)'

100000 loops, best of 3: 2.37 usec per loop

$ python -mtimeit -s'import re; x="aaa12333bab445bb54b5b52"' '"".join(re.findall("[a-z]+",x))'

100000 loops, best of 3: 1.97 usec per loop

I had observed that join is faster than sub.

You can read each character. If it is digit, then include it in the answer. The str.isdigit() method is a way to know if a character is digit.

your_input = '12kjkh2nnk34l34'
your_output = ''.join(c for c in your_input if c.isdigit())
print(your_output) # '1223434'

You can use join + filter + lambda:

''.join(filter(lambda s: s.isdigit(), "20 years ago, 2 months ago, 2 days ago"))

Output: '2022'

Not a one liner but very simple:

buffer = ""
some_str = "aas30dsa20"

for char in some_str:
    if not char.isdigit():
        buffer += char

print( buffer )

I used this. 'letters' should contain all the letters that you want to get rid of:

Output = Input.translate({ord(i): None for i in 'letters'}))

Example:

Input = "I would like 20 dollars for that suit" Output = Input.translate({ord(i): None for i in 'abcdefghijklmnopqrstuvwxzy'})) print(Output)

Output: 20

my_string="sdfsdfsdfsfsdf353dsg345435sdfs525436654.dgg(" 
my_string=''.join((ch if ch in '0123456789' else '') for ch in my_string)
print(output:+my_string)

output: 353345435525436654