Javascript set img src

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I am probably missing something simple but it's quite annoying when everything you read doesn't work. I have images which may be duplicated many times over the course of a dynamically generated page. So the obvious thing to do is to preload it and use that one variable as the source all the time.

var searchPic;
function LoadImages() {
    searchPic = new Image(100,100);
    searchPic.src = "XXXX/YYYY/search.png";
    // This is correct and the path is correct
}

then I set the image using

  document["pic1"].src = searchPic;

or

  $("#pic1").attr("src", searchPic);

However, the image is never set properly in FireBug when I query the image I get [object HTMLImageElement] as the src of the image

In IE I get:

http://localhost:8080/work/Sandbox/jpmetrix/[object]
10 Answers

You should be setting the src using this:

document["pic1"].src = searchPic.src;

or

$("#pic1").attr("src", searchPic.src);

Instances of the image constructor are not meant to be used anywhere. You simply set the src, and the image preloads...and that's it, show's over. You can discard the object and move on.

document["pic1"].src = "XXXX/YYYY/search.png"; 

is what you should be doing. You can still use the image constructor, and perform the second action in the onload handler of your searchPic. This ensures the image is loaded before you set the src on the real img object.

Like so:

function LoadImages() {
    searchPic = new Image();
    searchPic.onload=function () {
        document["pic1"].src = "XXXX/YYYY/search.png";
    }
    searchPic.src = "XXXX/YYYY/search.png"; // This is correct and the path is correct
}
document["pic1"].src = searchPic.src

should work

You don't need to construct a whole new image... the src attribute just takes a string value :-)

You need to set

document["pic1"].src = searchPic.src;

The searchPic itself is your Image(), you need to read the src that you set.

Your src property is an object because you are setting the src element to be the entire image you created in JavaScript.

Try

document["pic1"].src = searchPic.src;

Wow! when you use src then src of searchPic must be used also.

document["pic1"].src = searchPic.src

looks better

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