How does an inline function differ from a preprocessor macro?
How does an inline function differ from a preprocessor macro?
Preprocessor macros are just substitution patterns applied to your code. They can be used almost anywhere in your code because they are replaced with their expansions before any compilation starts.
Inline functions are actual functions whose body is directly injected into their call site. They can only be used where a function call is appropriate.
Now, as far as using macros vs. inline functions in a function-like context, be advised that:
First, the preprocessor macros are just "copy paste" in the code before the compilation. So there is no type checking, and some side effects can appear
For example, if you want to compare 2 values:
#define max(a,b) ((a<b)?b:a)
The side effects appear if you use max(a++,b++) for example (a or b will be incremented twice).
Instead, use (for example)
inline int max( int a, int b) { return ((a<b)?b:a); }
The key difference is type checking. The compiler will check whether what you pass as input values is of types that can be passed into the function. That's not true with preprocessor macros - they are expanded prior to any type checking and that can cause severe and hard to detect bugs.
Here are several other less obvious points outlined.
To add another difference to those already given: you can't step through a #define in the debugger, but you can step through an inline function.
inline functions are similar to macros (because the function code is expanded at the point of the call at compile time), inline functions are parsed by the compiler, whereas macros are expanded by the preprocessor. As a result, there are several important differences:
In some cases, expressions passed as arguments to macros can be evaluated more than once. http://msdn.microsoft.com/en-us/library/bf6bf4cf.aspx
macros are expanded at pre-compile time, you cannot use them for debugging, but you can use inline functions.
-- good article: http://www.codeguru.com/forum/showpost.php?p=1093923&postcount=1
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To know the difference between macros and inline functions, first we should know what exactly they are and when we should use them.
FUNCTIONS:
int Square(int x)
{
return(x*x);
}
int main()
{
int value = 5;
int result = Square(value);
cout << result << endl;
}
MACROS:
# define Square(x) x*x;
int main()
{
int value = 5;
int result = Square(value);
cout << result << endl;
}
#define keywords will be replaced or expandedint result = Square(x*x)
But macros can cause unexpected behavior.
#define Square(x) x*x
int main()
{
int val = 5;
int result = Square(val + 1);
cout << result << endl;
}
Here the output is 11, not 36.
INLINE FUNCTIONS:
inline int Square(int x)
{
return x * x;
}
int main()
{
int val = 5;
int result = Square(val + 1);
cout << result << endl;
}
Output: 36
The inline keyword requests that the compiler replace the function call with the body of the function. Here the output is correct because it first evaluates the expression and then uses the result to perform the body of the function. Inline functions reduce the function call overhead as there is no need to store a return address or function arguments to the stack.
Comparison Between Macros and Inline Functions:
CONCLUSION:
Inline functions are sometimes more useful than macros, as they are safe to use, but can also reduce function call overhead.
The inline keyword is a request to the compiler, certain functions won't be inlined like:
which is a good thing, because it allows the compiler to determine whether it would be better to do things another way.
An inline function will maintain value semantics, whereas a preprocessor macro just copies the syntax. You can get very subtle bugs with a preprocessor macro if you use the argument multiple times - for example if the argument contains mutation like "i++" having that execute twice is quite a surprise. An inline function will not have this problem.
A inline functuion behaves syntactically just like a normal function, providing type safety and a scope for function local variables and access to class-members if it is a method. Also when calling inline methods you must adhere to private/protected restrictions.
In GCC (I'm not sure about others), declaring a function inline, is just a hint to the compiler. It is still up to the compiler at the end of the day to decide whether or not it includes the body of the function whenever it is called.
The difference between in-line functions and preprocessor macros is relatively large. Preprocessor macros are just text replacement at the end of the day. You give up a lot of the ability for the compiler to perform checking on type checking on the arguments and return type. Evaluation of the arguments is much different (if the expressions you pass into the functions have side-effects you'll have a very fun time debugging). There are subtle differences about where functions and macros can be used. For example if I had:
#define MACRO_FUNC(X) ...
Where MACRO_FUNC obviously defines the body of the function. Special care needs to be taken so it runs correctly in all cases a function can be used, for example a poorly written MACRO_FUNC would cause an error in
if(MACRO_FUNC(y)) {
...body
}
A normal function could be used with no problem there.
From the perspective of coding, an inline function is like a function. Thus, the differences between an inline function and a macro are the same as the differences between a function and a macro.
From the perspective of compiling, an inline function is similar to a macro. It is injected directly into the code, not called.
In general, you should consider inline functions to be regular functions with some minor optimization mixed in. And like most optimizations, it is up to the compiler to decide if it actually cares to apply it. Often the compiler will happily ignore any attempts by the programmer to inline a function, for various reasons.