How may I sort a list alphabetically using jQuery?

Something like this:

var mylist = $('#myUL');
var listitems = mylist.children('li').get();
listitems.sort(function(a, b) {
   return $(a).text().toUpperCase().localeCompare($(b).text().toUpperCase());
})
$.each(listitems, function(idx, itm) { mylist.append(itm); });

From this page: http://www.onemoretake.com/2009/02/25/sorting-elements-with-jquery/

Above code will sort your unordered list with id 'myUL'.

OR you can use a plugin like TinySort. https://github.com/Sjeiti/TinySort

You do not need jQuery to do this...

function sortUnorderedList(ul, sortDescending) {
  if(typeof ul == "string")
    ul = document.getElementById(ul);

  // Idiot-proof, remove if you want
  if(!ul) {
    alert("The UL object is null!");
    return;
  }

  // Get the list items and setup an array for sorting
  var lis = ul.getElementsByTagName("LI");
  var vals = [];

  // Populate the array
  for(var i = 0, l = lis.length; i < l; i++)
    vals.push(lis[i].innerHTML);

  // Sort it
  vals.sort();

  // Sometimes you gotta DESC
  if(sortDescending)
    vals.reverse();

  // Change the list on the page
  for(var i = 0, l = lis.length; i < l; i++)
    lis[i].innerHTML = vals[i];
}

Easy to use...

sortUnorderedList("ID_OF_LIST");

Live Demo →

improvement based on Jeetendra Chauhan's answer

$('ul.menu').each(function(){
    $(this).children('li').sort((a,b)=>a.innerText.localeCompare(b.innerText)).appendTo(this);
});

why i consider it an improvement:

1. using each to support running on more than one ul

2. using children('li') instead of ('ul li') is important because we only want to process direct children and not descendants

3. using the arrow function (a,b)=> just looks better (IE not supported)

4. using vanilla innerText instead of $(a).text() for speed improvement

5. using vanilla localeCompare improves speed in case of equal elements (rare in real life usage)

6. using appendTo(this) instead of using another selector will make sure that even if the selector catches more than one ul still nothing breaks

HTML

<ul id="list">
    <li>alpha</li>
    <li>gamma</li>
    <li>beta</li>
</ul>

JavaScript

function sort(ul) {
    var ul = document.getElementById(ul)
    var liArr = ul.children
    var arr = new Array()
    for (var i = 0; i < liArr.length; i++) {
        arr.push(liArr[i].textContent)
    }
    arr.sort()
    arr.forEach(function(content, index) {
        liArr[index].textContent = content
    })
}

sort("list")

JSFiddle Demo https://jsfiddle.net/97oo61nw/

Here we are push all values of li elements inside ul with specific id (which we provided as function argument) to array arr and sort it using sort() method which is sorted alphabetical by default. After array arr is sorted we are loop this array using forEach() method and just replace text content of all li elements with sorted content