Sorting an array of objects by property values

Sort homes by price in ascending order:

homes.sort(function(a, b) {
    return parseFloat(a.price) - parseFloat(b.price);
});

Or after ES6 version:

homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));

Some documentation can be found here.

For descending order, you may use

homes.sort((a, b) => parseFloat(b.price) - parseFloat(a.price));

Here's a more flexible version, which allows you to create reusable sort functions, and sort by any field.

const sort_by = (field, reverse, primer) => {

  const key = primer ?
    function(x) {
      return primer(x[field])
    } :
    function(x) {
      return x[field]
    };

  reverse = !reverse ? 1 : -1;

  return function(a, b) {
    return a = key(a), b = key(b), reverse * ((a > b) - (b > a));
  }
}


//Now you can sort by any field at will...

const homes=[{h_id:"3",city:"Dallas",state:"TX",zip:"75201",price:"162500"},{h_id:"4",city:"Bevery Hills",state:"CA",zip:"90210",price:"319250"},{h_id:"5",city:"New York",state:"NY",zip:"00010",price:"962500"}];

// Sort by price high to low
console.log(homes.sort(sort_by('price', true, parseInt)));

// Sort by city, case-insensitive, A-Z
console.log(homes.sort(sort_by('city', false, (a) =>  a.toUpperCase()
)));

To sort it you need to create a comparator function taking two arguments. Then call the sort function with that comparator function as follows:

// a and b are object elements of your array
function mycomparator(a,b) {
  return parseInt(a.price, 10) - parseInt(b.price, 10);
}
homes.sort(mycomparator);

If you want to sort ascending switch the expressions on each side of the minus sign.

for string sorting in case some one needs it,

const dataArr = {

  "hello": [{
    "id": 114,
    "keyword": "zzzzzz",
    "region": "Sri Lanka",
    "supportGroup": "administrators",
    "category": "Category2"
  }, {
    "id": 115,
    "keyword": "aaaaa",
    "region": "Japan",
    "supportGroup": "developers",
    "category": "Category2"
  }]

};
const sortArray = dataArr['hello'];

console.log(sortArray.sort((a, b) => {
  if (a.region < b.region)
    return -1;
  if (a.region > b.region)
    return 1;
  return 0;
}));

You want to sort it in Javascript, right? What you want is the sort() function. In this case you need to write a comparator function and pass it to sort(), so something like this:

function comparator(a, b) {
    return parseInt(a["price"], 10) - parseInt(b["price"], 10);
}

var json = { "homes": [ /* your previous data */ ] };
console.log(json["homes"].sort(comparator));

Your comparator takes one of each of the nested hashes inside the array and decides which one is higher by checking the "price" field.

I'm little late for the party but below is my logic for sorting.

function getSortedData(data, prop, isAsc) {
    return data.sort((a, b) => {
        return (a[prop] < b[prop] ? -1 : 1) * (isAsc ? 1 : -1)
    });
}

You can use string1.localeCompare(string2) for string comparison

this.myArray.sort((a,b) => { 
    return a.stringProp.localeCompare(b.stringProp);
});

Note that localCompare is case insensitive

Descending order of price:

homes.sort((x,y) => {return y.price - x.price})

Ascending order of price:

homes.sort((x,y) => {return x.price - y.price})

While I am aware that the OP wanted to sort an array of numbers, this question has been marked as the answer for similar questions regarding strings. To that fact, the above answers do not consider sorting an array of text where casing is important. Most answers take the string values and convert them to uppercase/lowercase and then sort one way or another. The requirements that I adhere to are simple:

• Sort alphabetically A-Z
• Uppercase values of the same word should come before lowercase values
• Same letter (A/a, B/b) values should be grouped together

What I expect is [ A, a, B, b, C, c ] but the answers above return A, B, C, a, b, c. I actually scratched my head on this for longer than I wanted (which is why I am posting this in hopes that it will help at least one other person). While two users mention the localeCompare function in the comments for the marked answer, I didn't see that until after I stumbled upon the function while searching around. After reading the String.prototype.localeCompare() documentation I was able to come up with this:

var values = [ "Delta", "charlie", "delta", "Charlie", "Bravo", "alpha", "Alpha", "bravo" ];
var sorted = values.sort((a, b) => a.localeCompare(b, undefined, { caseFirst: "upper" }));
// Result: [ "Alpha", "alpha", "Bravo", "bravo", "Charlie", "charlie", "Delta", "delta" ]

This tells the function to sort uppercase values before lowercase values. The second parameter in the localeCompare function is to define the locale but if you leave it as undefined it automatically figures out the locale for you.

This works the same for sorting an array of objects as well:

var values = [
    { id: 6, title: "Delta" },
    { id: 2, title: "charlie" },
    { id: 3, title: "delta" },
    { id: 1, title: "Charlie" },
    { id: 8, title: "Bravo" },
    { id: 5, title: "alpha" },
    { id: 4, title: "Alpha" },
    { id: 7, title: "bravo" }
];
var sorted = values
    .sort((a, b) => a.title.localeCompare(b.title, undefined, { caseFirst: "upper" }));

You can use the JavaScript sort method with a callback function:

function compareASC(homeA, homeB)
{
    return parseFloat(homeA.price) - parseFloat(homeB.price);
}

function compareDESC(homeA, homeB)
{
    return parseFloat(homeB.price) - parseFloat(homeA.price);
}

// Sort ASC
homes.sort(compareASC);

// Sort DESC
homes.sort(compareDESC);

For a normal array of elements values only:

function sortArrayOfElements(arrayToSort) {
    function compareElements(a, b) {
        if (a < b)
            return -1;
        if (a > b)
            return 1;
        return 0;
    }

    return arrayToSort.sort(compareElements);
}

e.g. 1:
var array1 = [1,2,545,676,64,2,24]
output : [1, 2, 2, 24, 64, 545, 676]

var array2 = ["v","a",545,676,64,2,"24"]
output: ["a", "v", 2, "24", 64, 545, 676]

For an array of objects:

function sortArrayOfObjects(arrayToSort, key) {
    function compareObjects(a, b) {
        if (a[key] < b[key])
            return -1;
        if (a[key] > b[key])
            return 1;
        return 0;
    }

    return arrayToSort.sort(compareObjects);
}

e.g. 1: var array1= [{"name": "User4", "value": 4},{"name": "User3", "value": 3},{"name": "User2", "value": 2}]

output : [{"name": "User2", "value": 2},{"name": "User3", "value": 3},{"name": "User4", "value": 4}]

A more LINQ like solution:

Array.prototype.orderBy = function (selector, desc = false) {
    return [...this].sort((a, b) => {
        a = selector(a);
        b = selector(b);

        if (a == b) return 0;
        return (desc ? a > b : a < b) ? -1 : 1;
    });
}

Advantages:

• autocompletion for properties
• extends array prototype
• does not change array
• easy to use in method chaining

Usage:

Array.prototype.orderBy = function(selector, desc = false) {
  return [...this].sort((a, b) => {
    a = selector(a);
    b = selector(b);

    if (a == b) return 0;
    return (desc ? a > b : a < b) ? -1 : 1;
  });
};

var homes = [{
  "h_id": "3",
  "city": "Dallas",
  "state": "TX",
  "zip": "75201",
  "price": "162500"
}, {
  "h_id": "4",
  "city": "Bevery Hills",
  "state": "CA",
  "zip": "90210",
  "price": "319250"
}, {
  "h_id": "5",
  "city": "New York",
  "state": "NY",
  "zip": "00010",
  "price": "962500"
}];

let sorted_homes = homes.orderBy(h => parseFloat(h.price));
console.log("sorted by price", sorted_homes);

let sorted_homes_desc = homes.orderBy(h => h.city, true);
console.log("sorted by City descending", sorted_homes_desc);

Create a function and sort based on the input using below code

var homes = [{

    "h_id": "3",
    "city": "Dallas",
    "state": "TX",
    "zip": "75201",
    "price": "162500"

 }, {

    "h_id": "4",
    "city": "Bevery Hills",
    "state": "CA",
    "zip": "90210",
    "price": "319250"

 }, {

    "h_id": "5",
    "city": "New York",
    "state": "NY",
    "zip": "00010",
    "price": "962500"

 }];

 function sortList(list,order){
     if(order=="ASC"){
        return list.sort((a,b)=>{
            return parseFloat(a.price) - parseFloat(b.price);
        })
     }
     else{
        return list.sort((a,b)=>{
            return parseFloat(b.price) - parseFloat(a.price);
        });
     }
 }

 sortList(homes,'DESC');
 console.log(homes);

use this function

const r_sort = (a, b, field, asc) => {
    let reverse = asc ? 1 : -1;
    if (a[field] > b[field]) {
        return 1 * reverse;
    }
    else if (b[field] > a[field]) {
        return -1 * reverse;
    }
    else {
        return 0;
    } }

//usage:

homes = homes.sort((a,b) => r_sort(a,b,price,true)) // true for ascending and false for descending

A simple code :

    var homes = [
        {
            "h_id": "3",
            "city": "Dallas",
            "state": "TX",
            "zip": "75201",
            "price": "162500"
        }, {
            "h_id": "4",
            "city": "Bevery Hills",
            "state": "CA",
            "zip": "90210",
            "price": "319250"
        }, {
            "h_id": "5",
            "city": "New York",
            "state": "NY",
            "zip": "00010",
            "price": "962500"
        }
    ];

    let sortByPrice = homes.sort(function (a, b) 
    {
      return parseFloat(b.price) - parseFloat(a.price);
    });

    for (var i=0; i<sortByPrice.length; i++)
    {
      document.write(sortByPrice[i].h_id+' '+sortByPrice[i].city+' '
       +sortByPrice[i].state+' '
       +sortByPrice[i].zip+' '+sortByPrice[i].price);
      document.write("<br>");
    }

 function compareValues(key, order = 'asc') {
  return function innerSort(a, b) {
    if (!a.hasOwnProperty(key) || !b.hasOwnProperty(key)) {
      // property doesn't exist on either object
      return 0;
    }

    const varA = (typeof a[key] === 'string')
      ? a[key].toUpperCase() : a[key];
    const varB = (typeof b[key] === 'string')
      ? b[key].toUpperCase() : b[key];

    let comparison = 0;
    if (varA > varB) {
      comparison = 1;
    } else if (varA < varB) {
      comparison = -1;
    }
    return (
      (order === 'desc') ? (comparison * -1) : comparison
    );
  };
}

http://yazilimsozluk.com/sort-array-in-javascript-by-asc-or-desc

You can use the below approach if you don't want to use any sort() method

function sortObj(obj) {
  let numArr = []; //the array which just includes prices as Number
  let sortedObj = [];
  obj.map((x) => {
    numArr.push(Number(x["price"]));
  });

  while (numArr.length > 0) { 
    let minIndex = numArr.indexOf(Math.min(...numArr)); //the index of cheapest home in the obj
    numArr.splice(minIndex, 1); 
    sortedObj.push(obj.splice(minIndex, 1)); // splicing cheapest home from Homes Array to sortedObj Array.
  }

  console.log(sortedObj);
}

var homes = [
  {
    h_id: "3",
    city: "Dallas",
    state: "TX",
    zip: "75201",
    price: "162500",
  },
  {
    h_id: "4",
    city: "Bevery Hills",
    state: "CA",
    zip: "90210",
    price: "319250",
  },
  {
    h_id: "5",
    city: "New York",
    state: "NY",
    zip: "00010",
    price: "962500",
  },
];
sortObj(homes);