How to get the filename without the extension in Java?

The easiest way is to use a regular expression.

fileNameWithOutExt = "test.xml".replaceFirst("[.][^.]+$", "");

The above expression will remove the last dot followed by one or more characters. Here's a basic unit test.

public void testRegex() {
    assertEquals("test", "test.xml".replaceFirst("[.][^.]+$", ""));
    assertEquals("test.2", "test.2.xml".replaceFirst("[.][^.]+$", ""));
}

See the following test program:

public class javatemp {
    static String stripExtension (String str) {
        // Handle null case specially.

        if (str == null) return null;

        // Get position of last '.'.

        int pos = str.lastIndexOf(".");

        // If there wasn't any '.' just return the string as is.

        if (pos == -1) return str;

        // Otherwise return the string, up to the dot.

        return str.substring(0, pos);
    }

    public static void main(String[] args) {
        System.out.println ("test.xml   -> " + stripExtension ("test.xml"));
        System.out.println ("test.2.xml -> " + stripExtension ("test.2.xml"));
        System.out.println ("test       -> " + stripExtension ("test"));
        System.out.println ("test.      -> " + stripExtension ("test."));
    }
}

which outputs:

test.xml   -> test
test.2.xml -> test.2
test       -> test
test.      -> test

For Kotlin it's now simple as:

val fileNameStr = file.nameWithoutExtension

Simplest way to get name from relative path or full path is using

import org.apache.commons.io.FilenameUtils; FilenameUtils.getBaseName(definitionFilePath)

You can use java split function to split the filename from the extension, if you are sure there is only one dot in the filename which for extension.

File filename = new File('test.txt'); File.getName().split("[.]");

so the split[0] will return "test" and split[1] will return "txt"

fileEntry.getName().substring(0, fileEntry.getName().lastIndexOf("."));

Given the String filename, you can do:

String filename = "test.xml";
filename.substring(0, filename.lastIndexOf("."));   // Output: test
filename.split("\\.")[0];   // Output: test

public static String getFileExtension(String fileName) {
        if (TextUtils.isEmpty(fileName) || !fileName.contains(".") || fileName.endsWith(".")) return null;
        return fileName.substring(fileName.lastIndexOf(".") + 1);
    }

    public static String getBaseFileName(String fileName) {
        if (TextUtils.isEmpty(fileName) || !fileName.contains(".") || fileName.endsWith(".")) return null;
        return fileName.substring(0,fileName.lastIndexOf("."));
    }

The fluent way:

public static String fileNameWithOutExt (String fileName) {
    return Optional.of(fileName.lastIndexOf(".")).filter(i-> i >= 0)
            .filter(i-> i > fileName.lastIndexOf(File.separator))
            .map(i-> fileName.substring(0, i)).orElse(fileName);
}

You can split it by "." and on index 0 is file name and on 1 is extension, but I would incline for the best solution with FileNameUtils from apache.commons-io like it was mentioned in the first article. It does not have to be removed, but sufficent is:

String fileName = FilenameUtils.getBaseName("test.xml");

Use FilenameUtils.removeExtension from Apache Commons IO

Example:

You can provide full path name or only the file name.

String myString1 = FilenameUtils.removeExtension("helloworld.exe"); // returns "helloworld"
String myString2 = FilenameUtils.removeExtension("/home/abc/yey.xls"); // returns "yey"

Hope this helps ..

Keeping it simple, use Java's String.replaceAll() method as follows:

String fileNameWithExt = "test.xml";
String fileNameWithoutExt
   = fileNameWithExt.replaceAll( "^.*?(([^/\\\\\\.]+))\\.[^\\.]+$", "$1" );

This also works when fileNameWithExt includes the fully qualified path.

My solution needs the following import.

import java.io.File;

The following method should return the desired output string:

private static String getFilenameWithoutExtension(File file) throws IOException {
    String filename = file.getCanonicalPath();
    String filenameWithoutExtension;
    if (filename.contains("."))
        filenameWithoutExtension = filename.substring(filename.lastIndexOf(System.getProperty("file.separator"))+1, filename.lastIndexOf('.'));
    else
        filenameWithoutExtension = filename.substring(filename.lastIndexOf(System.getProperty("file.separator"))+1);

    return filenameWithoutExtension;
}

com.google.common.io.Files

Files.getNameWithoutExtension(sourceFile.getName())

can do a job as well