Python strftime - date without leading 0?

Actually I had the same problem and I realized that, if you add a hyphen between the % and the letter, you can remove the leading zero.

For example %Y/%-m/%-d.

This only works on Unix (Linux, OS X), not Windows (including Cygwin). On Windows, you would use #, e.g. %Y/%#m/%#d.

Some platforms may support width and precision specification between % and the letter (such as 'd' for day of month), according to http://docs.python.org/library/time.html -- but it's definitely a non-portable solution (e.g. doesn't work on my Mac;-). Maybe you can use a string replace (or RE, for really nasty format) after the strftime to remedy that? e.g.:

>>> y
(2009, 5, 7, 17, 17, 17, 3, 127, 1)
>>> time.strftime('%Y %m %d', y)
'2009 05 07'
>>> time.strftime('%Y %m %d', y).replace(' 0', ' ')
'2009 5 7'

Here is the documentation of the modifiers supported by strftime() in the GNU C library. (Like people said before, it might not be portable.) Of interest to you might be:

• %e instead of %d will replace leading zero in day of month with a space

It works on my Python (on Linux). I don't know if it will work on yours.

Because Python really just calls the C language strftime(3) function on your platform, it might be that there are format characters you could use to control the leading zero; try man strftime and take a look. But, of course, the result will not be portable, as the Python manual will remind you. :-)

I would try using a new-style datetime object instead, which has attributes like t.year and t.month and t.day, and put those through the normal, high-powered formatting of the % operator, which does support control of leading zeros. See http://docs.python.org/library/datetime.html for details. Better yet, use the "".format() operator if your Python has it and be even more modern; it has lots of format options for numbers as well. See: http://docs.python.org/library/string.html#string-formatting.

if we want to fetch only date without leading zero we can

d = date.today()
day = int(d.strftime("%d"))

Python 3.6+:

from datetime import date
today = date.today()
text = "Today it is " + today.strftime(f"%A %B {today.day}, %Y")

I am late, but a simple list slicing will do the work

today_date = date.today().strftime('%d %b %Y')
if today_date[0] == '0':
    today_date = today_date[1:]

The standard library is good enough for most cases but for a really detailed manipulation with dates you should always look for some specialized third-party library.

Using Arrow:

>>> import arrow
>>> arrow.utcnow().format('dddd, D. M. YYYY')
'Friday, 6. 5. 2022'

Look at the full list of supported tokens.