How to display a date as iso 8601 format with PHP

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I'm trying to display a datetime from my MySQL database as an iso 8601 formated string with PHP but it's coming out wrong.

17 Oct 2008 is coming out as: 1969-12-31T18:33:28-06:00 which is clearly not correct (the year should be 2008 not 1969)

This is the code I'm using:

<?= date("c", $post[3]) ?>

$post[3] is the datetime (CURRENT_TIMESTAMP) from my MySQL database.

Any ideas what's going wrong?

6 Answers

The second argument of date is a UNIX timestamp, not a database timestamp string.

You need to convert your database timestamp with strtotime.

<?= date("c", strtotime($post[3])) ?>

The problem many times occurs with the milliseconds and final microseconds that many times are in 4 or 8 finals. To convert the DATE to ISO 8601 "date(DATE_ISO8601)" these are one of the solutions that works for me:

// In this form it leaves the date as it is without taking the current date as a reference
$dt = new DateTime();
echo $dt->format('Y-m-d\TH:i:s.').substr($dt->format('u'),0,3).'Z';
// return-> 2020-05-14T13:35:55.191Z

// In this form it takes the reference of the current date
echo date('Y-m-d\TH:i:s'.substr((string)microtime(), 1, 4).'\Z');
return-> 2020-05-14T13:35:55.191Z

// Various examples:
$date_in = '2020-05-25 22:12 03.056';
$dt = new DateTime($date_in);
echo $dt->format('Y-m-d\TH:i:s.').substr($dt->format('u'),0,3).'Z';
// return-> 2020-05-25T22:12:03.056Z

//In this form it takes the reference of the current date
echo date('Y-m-d\TH:i:s'.substr((string)microtime(), 1, 4).'\Z',strtotime($date_in));
// return-> 2020-05-25T14:22:05.188Z
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