Removing carriage return and new-line from the end of a string in c#

This will trim off any combination of carriage returns and newlines from the end of s:

s = s.TrimEnd(new char[] { '\r', '\n' });

Edit: Or as JP kindly points out, you can spell that more succinctly as:

s = s.TrimEnd('\r', '\n');

This should work ...

var tst = "12345\n\n\r\n\r\r";
var res = tst.TrimEnd( '\r', '\n' );

String temp = s.Replace("\r\n","").Trim();

s being the original string. (Note capitals)

If there's always a single CRLF, then:

myString = myString.Substring(0, myString.Length - 2);

If it may or may not have it, then:

Regex re = new Regex("\r\n$");
re.Replace(myString, "");

Both of these (by design), will remove at most a single CRLF. Cache the regex for performance.

I use lots of erasing level

String donen = "lots of stupid whitespaces and new lines and others..."

//Remove multilines
donen = Regex.Replace(donen, @"^\s+$[\r\n]*", "", RegexOptions.Multiline);
//remove multi whitespaces
RegexOptions options = RegexOptions.None;
Regex regex = new Regex("[ ]{2,}", options);
donen = regex.Replace(donen, " ");
//remove tabs
char tab = '\u0009';
donen = donen.Replace(tab.ToString(), "");
//remove endoffile newlines
donen = donen.TrimEnd('\r', '\n');
//to be sure erase new lines again from another perspective
donen.Replace(Environment.NewLine, "");

and now we have a clean one row

This is what I got to work for me.

s.Replace("\r","").Replace("\n","")

If you use the nuget IvanStoychev.Useful.String.Extensions you can do:

s = s.TrimEnd(Environment.Newline);

It adds an overload of TrimEnd that takes a string.