How to get "GET" request parameters in JavaScript?

Viewed 305906

How to get "GET" variables from request in JavaScript?

Does jQuery or YUI! have this feature built-in?

12 Answers

Update June 2021:

Today's browsers have built-in APIs for working with URLs (URL) and query strings (URLSearchParams) and these should be preferred, unless you need to support some old browsers or Opera mini (Browser support).

Original:

All data is available under

window.location.search

you have to parse the string, eg.

function get(name){
   if(name=(new RegExp('[?&]'+encodeURIComponent(name)+'=([^&]*)')).exec(location.search))
      return decodeURIComponent(name[1]);
}

just call the function with GET variable name as parameter, eg.

get('foo');

this function will return the variables value or undefined if variable has no value or doesn't exist

Unlike other answers, the UrlSearchParams object can avoid using Regexes or other string manipulation and is available is most modern browsers:

var queryString = location.search
let params = new URLSearchParams(queryString)
// example of retrieving 'id' parameter
let id = parseInt(params.get("id"))
console.log(id)

You can use the URL to acquire the GET variables. In particular, window.location.search gives everything after (and including) the '?'. You can read more about window.location here.

You can parse the URL of the current page to obtain the GET parameters. The URL can be found by using location.href.

Works for me in

url: http://localhost:8080/#/?access_token=111

function get(name){
  const parts = window.location.href.split('?');
  if (parts.length > 1) {
    name = encodeURIComponent(name);
    const params = parts[1].split('&');
    const found = params.filter(el => (el.split('=')[0] === name) && el);
    if (found.length) return decodeURIComponent(found[0].split('=')[1]);
  }
}
Related