Loop through JSON object List

user_56256 0
Viewed 385405

I am returning a List<> from a webservice as a List of JSON objects. I am trying to use a for loop to iterate through the list and grab the values out of the properties. This is a sample of the returning JSON:

{"d":[{"__type":"FluentWeb.DTO.EmployeeOrder",
 "EmployeeName":"Janet Leverling",
 "EmployeeTitle":"Sales Representative",
 "RequiredDate":"\/Date(839224800000)\/",
 "OrderedProducts":null}]}

So I am trying to extract the contents using something like this:

function PrintResults(result) {

for (var i = 0; i < result.length; i++) { 
    alert(result.employeename);
}

How should this be done?

web-services jquery json javascript
8 Answers

Be careful, d is the list.

for (var i = 0; i < result.d.length; i++) { 
    alert(result.d[i].employeename);
}
user_926060

had same problem today, Your topic helped me so here goes solution ;)

 alert(result.d[0].EmployeeTitle);
Admin1

It's close! Try this:

for (var prop in result) {
    if (result.hasOwnProperty(prop)) {
        alert(result[prop]);
    }
}

Update:

If your result is truly is an array of one object, then you might have to do this:

for (var prop in result[0]) {
    if (result[0].hasOwnProperty(prop)) {
        alert(result[0][prop]);
    }
}

Or if you want to loop through each result in the array if there are more, try:

for (var i = 0; i < results.length; i++) {
    for (var prop in result[i]) {
        if (result[i].hasOwnProperty(prop)) {
            alert(result[i][prop]);
        }
    }
}
user_747570

Since you are using jQuery, you might as well use the each method... Also, it seems like everything is a value of the property 'd' in this JS Object [Notation]. 

$.each(result.d,function(i) {
    // In case there are several values in the array 'd'
    $.each(this,function(j) {
        // Apparently doesn't work...
        alert(this.EmployeeName);
        // What about this?
        alert(result.d[i][j]['EmployeeName']);
        // Or this?
        alert(result.d[i][j].EmployeeName);
    });
});

That should work. if not, then maybe you can give us a longer example of the JSON.

Edit: If none of this stuff works then I'm starting to think there might be something wrong with the syntax of your JSON.

user_833040
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