Submitting a form on 'Enter' with jQuery?

In addition to return false as Jason Cohen mentioned. You may have to also preventDefault

e.preventDefault();

Don't know if it will help, but you can try simulating a submit button click, instead of directly submitting the form. I have the following code in production, and it works fine:

    $('.input').keypress(function(e) {
        if(e.which == 13) {
            jQuery(this).blur();
            jQuery('#submit').focus().click();
        }
    });

Note: jQuery('#submit').focus() makes the button animate when enter is pressed.

Return false to prevent the keystroke from continuing.

Is there any reason you have to hook and test for the enter key?

Couldn't you simply add a

<input type="submit" /> 

to your form and have it naturally be submitted when enter is pushed? You could even then hook the form's onsubmit action and call a validation function from there if you wanted...

You could even use the onsubmit as a test to see if your form is being submitted, but it won't work if you call form.submit().

Also to maintain accessibility, you should use this to determine your keycode:

c = e.which ? e.which : e.keyCode;

if (c == 13) ...

I found out today the keypress event is not fired when hitting the Enter key, so you might want to switch to keydown() or keyup() instead.

My test script:

        $('.module input').keydown(function (e) {
            var keyCode = e.which;
            console.log("keydown ("+keyCode+")")
            if (keyCode == 13) {
                console.log("enter");
                return false;
            }
        });
        $('.module input').keyup(function (e) {
            var keyCode = e.which;
            console.log("keyup ("+keyCode+")")
            if (keyCode == 13) {
                console.log("enter");
                return false;
            }
        });
        $('.module input').keypress(function (e) {
            var keyCode = e.which;
            console.log("keypress ("+keyCode+")");
            if (keyCode == 13) {
                console.log("Enter");
                return false;
            }
        });

The output in the console when typing "A Enter B" on the keyboard:

keydown (65)
keypress (97)
keyup (65)

keydown (13)
enter
keyup (13)
enter

keydown (66)
keypress (98)
keyup (66)

You see in the second sequence the 'keypress' is missing, but keydown and keyup register code '13' as being pressed/released. As per jQuery documentation on the function keypress():

Note: as the keypress event isn't covered by any official specification, the actual behavior encountered when using it may differ across browsers, browser versions, and platforms.

Tested on IE11 and FF61 on Server 2012 R2

As it may be late but you can add below line in html:-

<input onkeyup="submitForm(event)" oninput="addTextName(this)" type="text" id="name-val">

and add this on js file

function submitForm(e) {
var keyCode = e.keyCode ? e.keyCode : e.which;
if (keyCode == 13){
    toggleNextScreen();
}

}

keycode 13 means enter

In HTML codes:

<form action="POST" onsubmit="ajax_submit();return false;">
    <b>First Name:</b> <input type="text" name="firstname" id="firstname">
    <br>
    <b>Last Name:</b> <input type="text" name="lastname" id="lastname">
    <br>
    <input type="submit" name="send" onclick="ajax_submit();">
</form>

In Js codes:

function ajax_submit()
{
    $.ajax({
        url: "submit.php",
        type: "POST",
        data: {
            firstname: $("#firstname").val(),
            lastname: $("#lastname").val()
        },
        dataType: "JSON",
        success: function (jsonStr) {
            // another codes when result is success
        }
    });
}

$('form#login').keypress(function (e) {
   var keyCode = e.keyCode ? e.keyCode : e.which;       
   if (keyCode == 13) 
   {
      e.preventDefault();
      $('form#login').submit();
      return false; 
   }
});