Simplest way to increment a date in PHP?

user_14569 0
Viewed 95903

Say I have a string coming in, "2007-02-28", what's the simplest code I could write to turn that into "2007-03-01"? Right now I'm just using strtotime(), then adding 24*60*60, then using date(), but just wondering if there is a cleaner, simpler, or more clever way of doing it.

date-manipulation strtotime date datetime php
9 Answers

A clean way is to use strtotime()

$date = strtotime("+1 day", strtotime("2007-02-28"));
echo date("Y-m-d", $date);

Will give you the 2007-03-01

211lafur_Waage_224590

It's cleaner and simpler to add 86400. :)

The high-tech way is to do:

$date = new DateTime($input_date);
$date->modify('+1 day');
echo $date->format('Y-m-d');

but that's really only remotely worthwhile if you're doing, say, a sequence of transformations on the date, rather than just finding tomorrow.

user_475290

You can do the addition right inside strtotime, e.g.

 $today="2007-02-28";
 $nextday=strftime("%Y-%m-%d", strtotime("$today +1 day"));
Paul_Dixon_65210

Another way is to use function mktime(). It is very useful function...

$date = "2007-02-28";
list($y,$m,$d)=explode('-',$date);
$date2 = Date("Y-m-d", mktime(0,0,0,$m,$d+1,$y));

but I think strtotime() is better in that situation...

user_3916840 
$your_date = strtotime("1month", strtotime(date("Y-m-d")));
 $new_date = date("Y-m-d", $your_date++);
user_88041070

use strtotime() With date Formate

echo date('Y-m-d', strtotime('2007-02-28' . ' +1 day'));
user_118828730
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