Getting the class name of an instance

Have you tried the __name__ attribute of the class? ie type(x).__name__ will give you the name of the class, which I think is what you want.

>>> import itertools
>>> x = itertools.count(0)
>>> type(x).__name__
'count'

If you're still using Python 2, note that the above method works with new-style classes only (in Python 3+ all classes are "new-style" classes). Your code might use some old-style classes. The following works for both:

x.__class__.__name__

Do you want the name of the class as a string?

instance.__class__.__name__

type() ?

>>> class A:
...     def whoami(self):
...         print(type(self).__name__)
...
>>>
>>> class B(A):
...     pass
...
>>>
>>>
>>> o = B()
>>> o.whoami()
'B'
>>>

You can simply use __qualname__ which stands for qualified name of a function or class

Example:

>>> class C:
...     class D:
...         def meth(self):
...             pass
...
>>> C.__qualname__
'C'
>>> C.D.__qualname__
'C.D'
>>> C.D.meth.__qualname__
'C.D.meth'

documentation link qualname

To get instance classname:

type(instance).__name__

or

instance.__class__.__name__

both are the same

You can first use type and then str to extract class name from it.

class foo:pass;

bar:foo=foo();
print(str(type(bar))[8:-2][len(str(type(bar).__module__))+1:]);

Result

foo