Assume the following type definitions:
public interface IFoo<T> : IBar<T> {}
public class Foo<T> : IFoo<T> {}
How do I find out whether the type Foo implements the generic interface IBar<T> when only the mangled type is available?
Assume the following type definitions:
public interface IFoo<T> : IBar<T> {}
public class Foo<T> : IFoo<T> {}
How do I find out whether the type Foo implements the generic interface IBar<T> when only the mangled type is available?
By using the answer from TcKs it can also be done with the following LINQ query:
bool isBar = foo.GetType().GetInterfaces().Any(x =>
x.IsGenericType &&
x.GetGenericTypeDefinition() == typeof(IBar<>));
You have to go up through the inheritance tree and find all the interfaces for each class in the tree, and compare typeof(IBar<>) with the result of calling Type.GetGenericTypeDefinition if the interface is generic. It's all a bit painful, certainly.
See this answer and these ones for more info and code.
public interface IFoo<T> : IBar<T> {}
public class Foo : IFoo<Foo> {}
var implementedInterfaces = typeof( Foo ).GetInterfaces();
foreach( var interfaceType in implementedInterfaces ) {
if ( false == interfaceType.IsGeneric ) { continue; }
var genericType = interfaceType.GetGenericTypeDefinition();
if ( genericType == typeof( IFoo<> ) ) {
// do something !
break;
}
}
You have to check against a constructed type of the generic interface.
You will have to do something like this:
foo is IBar<String>
because IBar<String> represents that constructed type. The reason you have to do this is because if T is undefined in your check, the compiler doesn't know if you mean IBar<Int32> or IBar<SomethingElse>.
First of all public class Foo : IFoo<T> {} does not compile because you need to specify a class instead of T, but assuming you do something like public class Foo : IFoo<SomeClass> {}
then if you do
Foo f = new Foo();
IBar<SomeClass> b = f as IBar<SomeClass>;
if(b != null) //derives from IBar<>
Blabla();
Try the following extension.
public static bool Implements(this Type @this, Type @interface)
{
if (@this == null || @interface == null) return false;
return @interface.GenericTypeArguments.Length>0
? @interface.IsAssignableFrom(@this)
: @this.GetInterfaces().Any(c => c.Name == @interface.Name);
}
To test it. create
public interface IFoo { }
public interface IFoo<T> : IFoo { }
public interface IFoo<T, M> : IFoo<T> { }
public class Foo : IFoo { }
public class Foo<T> : IFoo { }
public class Foo<T, M> : IFoo<T> { }
public class FooInt : IFoo<int> { }
public class FooStringInt : IFoo<string, int> { }
public class Foo2 : Foo { }
and the test method
public void Test()
{
Console.WriteLine(typeof(Foo).Implements(typeof(IFoo)));
Console.WriteLine(typeof(FooInt).Implements(typeof(IFoo)));
Console.WriteLine(typeof(FooInt).Implements(typeof(IFoo<>)));
Console.WriteLine(typeof(FooInt).Implements(typeof(IFoo<int>)));
Console.WriteLine(typeof(FooInt).Implements(typeof(IFoo<string>)));
Console.WriteLine(typeof(FooInt).Implements(typeof(IFoo<,>)));
Console.WriteLine(typeof(FooStringInt).Implements(typeof(IFoo<,>)));
Console.WriteLine(typeof(FooStringInt).Implements(typeof(IFoo<string,int>)));
Console.WriteLine(typeof(Foo<int,string>).Implements(typeof(IFoo<string>)));
}
var genericType = typeof(ITest<>);
Console.WriteLine(typeof(Test).GetInterfaces().Any(x => x.GetGenericTypeDefinition().Equals(genericType))); // prints: "True"
interface ITest<T> { };
class Test : ITest<string> { }
This worked for me.