How to delete an element from an array in C#

If you want to remove all instances of 4 without needing to know the index:

LINQ: (.NET Framework 3.5)

int[] numbers = { 1, 3, 4, 9, 2 };
int numToRemove = 4;
numbers = numbers.Where(val => val != numToRemove).ToArray();

Non-LINQ: (.NET Framework 2.0)

static bool isNotFour(int n)
{
    return n != 4;
}

int[] numbers = { 1, 3, 4, 9, 2 };
numbers = Array.FindAll(numbers, isNotFour).ToArray();

If you want to remove just the first instance:

LINQ: (.NET Framework 3.5)

int[] numbers = { 1, 3, 4, 9, 2, 4 };
int numToRemove = 4;
int numIndex = Array.IndexOf(numbers, numToRemove);
numbers = numbers.Where((val, idx) => idx != numIndex).ToArray();

Non-LINQ: (.NET Framework 2.0)

int[] numbers = { 1, 3, 4, 9, 2, 4 };
int numToRemove = 4;
int numIdx = Array.IndexOf(numbers, numToRemove);
List<int> tmp = new List<int>(numbers);
tmp.RemoveAt(numIdx);
numbers = tmp.ToArray();

Edit: Just in case you hadn't already figured it out, as Malfist pointed out, you need to be targetting the .NET Framework 3.5 in order for the LINQ code examples to work. If you're targetting 2.0 you need to reference the Non-LINQ examples.

You can also convert your array to a list and call remove on the list. You can then convert back to your array.

int[] numbers = {1, 3, 4, 9, 2};
var numbersList = numbers.ToList();
numbersList.Remove(4);

The code that is written in the question has a bug in it

Your arraylist contains strings of " 1" " 3" " 4" " 9" and " 2" (note the spaces)

So IndexOf(4) will find nothing because 4 is an int, and even "tostring" would convert it to of "4" and not " 4", and nothing will get removed.

An arraylist is the correct way to go to do what you want.

Removing from an array itself is not simple, as you then have to deal with resizing. This is one of the great advantages of using something like a List<int> instead. It provides Remove/RemoveAt in 2.0, and lots of LINQ extensions for 3.0.

If you can, refactor to use a List<> or similar.

Balabaster's answer is correct if you want to remove all instances of the element. If you want to remove only the first one, you would do something like this:

int[] numbers = { 1, 3, 4, 9, 2, 4 };
int numToRemove = 4;
int firstFoundIndex = Array.IndexOf(numbers, numToRemove);
if (numbers >= 0)
{
    numbers = numbers.Take(firstFoundIndex).Concat(numbers.Skip(firstFoundIndex + 1)).ToArray();
}

You can do in this way:

int[] numbers= {1,3,4,9,2};     
List<int> lst_numbers = new List<int>(numbers);
int required_number = 4;
int i = 0;
foreach (int number in lst_numbers)
{              
    if(number == required_number)
    {
        break;
    }
    i++;
}
lst_numbers.RemoveAt(i);
numbers = lst_numbers.ToArray();        

' To remove items from string based on Dictionary key values. ' VB.net code

 Dim stringArr As String() = "file1,file2,file3,file4,file5,file6".Split(","c)
 Dim test As Dictionary(Of String, String) = New Dictionary(Of String, String)
 test.Add("file3", "description")
 test.Add("file5", "description")
 stringArr = stringArr.Except(test.Keys).ToArray()

    public int[] DeletePart(int position, params int[] numbers)
    {
        int[] result = new int[numbers.Length - 1];
        int z=0;

        for (int i = 0; i < numbers.Length; i++)
        {
            if (position - 1 != i)
            {
                result[z] = numbers[i];
                z++;
            }
        }
        return result;
    }

We can delete array elements by using for loops and continue statements:

string[] cars = {"volvo", "benz", "ford", "bmw"};
for (int i = 0; i < cars.Length; i++)
{
    if (cars[i] == "benz")
    {
        continue;
    }
    Console.WriteLine(cars[i]);
}