I would like to have a regular expression that checks if a string contains only upper and lowercase letters, numbers, and underscores.
I would like to have a regular expression that checks if a string contains only upper and lowercase letters, numbers, and underscores.
To match a string that contains only those characters (or an empty string), try
"^[a-zA-Z0-9_]*$"
This works for .NET regular expressions, and probably a lot of other languages as well.
Breaking it down:
^ : start of string
[ : beginning of character group
a-z : any lowercase letter
A-Z : any uppercase letter
0-9 : any digit
_ : underscore
] : end of character group
* : zero or more of the given characters
$ : end of string
If you don't want to allow empty strings, use + instead of *.
As others have pointed out, some regex languages have a shorthand form for [a-zA-Z0-9_]. In the .NET regex language, you can turn on ECMAScript behavior and use \w as a shorthand (yielding ^\w*$ or ^\w+$). Note that in other languages, and by default in .NET, \w is somewhat broader, and will match other sorts of Unicode characters as well (thanks to Jan for pointing this out). So if you're really intending to match only those characters, using the explicit (longer) form is probably best.
There's a lot of verbosity in here, and I'm deeply against it, so, my conclusive answer would be:
/^\w+$/
\w is equivalent to [A-Za-z0-9_], which is pretty much what you want. (unless we introduce unicode to the mix)
Using the + quantifier you'll match one or more characters. If you want to accept an empty string too, use * instead.
You want to check that each character matches your requirements, which is why we use:
[A-Za-z0-9_]
And you can even use the shorthand version:
\w
Which is equivalent (in some regex flavors, so make sure you check before you use it). Then to indicate that the entire string must match, you use:
^
To indicate the string must start with that character, then use
$
To indicate the string must end with that character. Then use
\w+ or \w*
To indicate "1 or more", or "0 or more". Putting it all together, we have:
^\w*$
Um...question: Does it need to have at least one character or no? Can it be an empty string?
^[A-Za-z0-9_]+$
Will do at least one upper or lower case alphanumeric or underscore. If it can be zero length, then just substitute the + for *
^[A-Za-z0-9_]*$
Edit:
If diacritics need to be included (such as cedilla - ç) then you would need to use the word character which does the same as the above, but includes the diacritic characters:
^\w+$
Or
^\w*$
How about:
^([A-Za-z]|[0-9]|_)+$
...if you want to be explicit, or:
^\w+$
...if you prefer concise (Perl syntax).
This works for me, found this in the O'Reilly's "Mastering Regular Expressions":
/^\w+$/
Explanation:
Verify yourself:
const regex = /^\w+$/;
const str = `nut_cracker_12`;
let m;
if ((m = regex.exec(str)) !== null) {
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
The following regex matches alphanumeric characters and underscore:
^[a-zA-Z0-9_]+$
For example, in Perl:
#!/usr/bin/perl -w
my $arg1 = $ARGV[0];
# check that the string contains *only* one or more alphanumeric chars or underscores
if ($arg1 !~ /^[a-zA-Z0-9_]+$/) {
print "Failed.\n";
} else {
print "Success.\n";
}
This should work in most of the cases.
/^[\d]*[a-z_][a-z\d_]*$/gi
And by most I mean,
abcd True
abcd12 True
ab12cd True
12abcd True
1234 False
^ ... $ - match the pattern starting and ending with[\d]* - match zero or more digits[a-z_] - match an alphabet or underscore[a-z\d_]* - match an alphabet or digit or underscore/gi - match globally across the string and case-insensitiveFor those of you looking for unicode alphanumeric matching, you might want to do something like:
^[\p{L} \p{Nd}_]+$
Further reading at http://unicode.org/reports/tr18/ and at http://www.regular-expressions.info/unicode.html
Here is the regex for what you want with a quantifier to specify at least 1 character and no more than 255 characters
[^a-zA-Z0-9 _]{1,255}
I believe you are not taking Latin and Unicode characters in your matches. For example, if you need to take "ã" or "ü" chars, the use of "\w" won't work.
You can, alternatively, use this approach:
^[A-ZÀ-Ýa-zà-ý0-9_]+$
Hope it helps!
For Java, Only case insensitive alphanumeric and underscore are allowed.
public class RegExTest { public static void main(String[] args) { System.out.println("_C#".matches("^[a-zA-Z0-9_]+$")); } }
Required Format Allow these 3:
Don't Allow other formats:
validatePnrAndTicketNumber(){
let alphaNumericRegex=/^[a-zA-Z0-9]*$/;
let numericRegex=/^[0-9]*$/;
let numericdashRegex=/^(([1-9]{3})\-?([0-9]{10}))$/;
this.currBookingRefValue = this.requestForm.controls["bookingReference"].value;
if(this.currBookingRefValue.length == 14 && this.currBookingRefValue.match(numericdashRegex)){
this.requestForm.controls["bookingReference"].setErrors({'pattern': false});
}else if(this.currBookingRefValue.length ==6 && this.currBookingRefValue.match(alphaNumericRegex)){
this.requestForm.controls["bookingReference"].setErrors({'pattern': false});
}else if(this.currBookingRefValue.length ==13 && this.currBookingRefValue.match(numericRegex) ){
this.requestForm.controls["bookingReference"].setErrors({'pattern': false});
}else{
this.requestForm.controls["bookingReference"].setErrors({'pattern': true});
}
}
<input name="booking_reference" type="text" [class.input-not-empty]="bookingRef.value"
class="glyph-input form-control floating-label-input" id="bookings_bookingReference"
value="" maxlength="14" aria-required="true" role="textbox" #bookingRef
formControlName="bookingReference" (focus)="resetMessageField()" (blur)="validatePnrAndTicketNumber()"/>