I've been using this function but I'd like to know what's the most efficient and accurate way to get it.
function daysInMonth(iMonth, iYear) {
return 32 - new Date(iYear, iMonth, 32).getDate();
}
I've been using this function but I'd like to know what's the most efficient and accurate way to get it.
function daysInMonth(iMonth, iYear) {
return 32 - new Date(iYear, iMonth, 32).getDate();
}
function daysInMonth (month, year) { // Use 1 for January, 2 for February, etc.
return new Date(year, month, 0).getDate();
}
console.log(daysInMonth(2, 1999)); // February in a non-leap year.
console.log(daysInMonth(2, 2000)); // February in a leap year.
Day 0 is the last day in the previous month. Because the month constructor is 0-based, this works nicely. A bit of a hack, but that's basically what you're doing by subtracting 32.
See more : Number of days in the current month
May be bit over kill when compared to selected answer :) But here it is:
function getDayCountOfMonth(year, month) {
if (month === 3 || month === 5 || month === 8 || month === 10) {
return 30;
}
if (month === 1) {
if (year % 4 === 0 && year % 100 !== 0 || year % 400 === 0) {
return 29;
} else {
return 28;
}
}
return 31;
};
console.log(getDayCountOfMonth(2020, 1));
I found the above code over here: https://github.com/ElemeFE/element/blob/dev/src/utils/date-util.js
function isLeapYear(year) {
return ((year % 4 === 0 && year % 100 !== 0) || year % 400 === 0);
};
const getDaysInMonth = function (year, month) {
return [31, (isLeapYear(year) ? 29 : 28), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31][month];
};
console.log(getDaysInMonth(2020, 1));
I found the above code over here: https://github.com/datejs/Datejs/blob/master/src/core.js
ES6 syntax
const d = (y, m) => new Date(y, m, 0).getDate();
returns
console.log( d(2020, 2) );
// 29
console.log( d(2020, 6) );
// 30
In a single line:
// month is 1-12
function getDaysInMonth(year, month){
return month == 2 ? 28 + (year % 4 == 0 ? (year % 100 == 0 ? (year % 400 == 0 ? 1 : 0) : 1):0) : 31 - (month - 1) % 7 % 2;
}
Perhaps not the most elegant solution, but easy to understand and maintain; and, it's battle-tested.
function daysInMonth(month, year) {
var days;
switch (month) {
case 1: // Feb, our problem child
var leapYear = ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
days = leapYear ? 29 : 28;
break;
case 3: case 5: case 8: case 10:
days = 30;
break;
default:
days = 31;
}
return days;
},
If you are going to pass a date variable this may helpful
const getDaysInMonth = date =>
new Date(date.getFullYear(), date.getMonth() + 1, 0).getDate();
daysInThisMonth = getDaysInMonth(new Date());
console.log(daysInThisMonth);
One-liner, without using Date objects:
const countDays = (month, year) => 30 + (month === 2 ? (year % 4 === 0 && 1) - 2 : (month + Number(month > 7)) % 2);
returns:
countDays(11,2020) // 30
countDays(2,2020) // 29
countDays(2,2021) // 28
To get the number of days in the current month
var nbOfDaysInCurrentMonth = new Date(Date.UTC(new Date().getUTCFullYear(), new Date().getUTCMonth(), 0)).getDate()
console.log(nbOfDaysInCurrentMonth)
Try this - it returns dictionary with month: days mapping, I think it will be very useful in most cases when people enter this topic:
const getMonthsDaysForYear = (year) => {
let monthDaysDictionary = {};
for(let i = 1; i <= 11; i++) {
const date = new Date(year, i + 1, 0);
const monthName = date.toLocaleString('en-GB', { month: 'long' });
monthDaysDictionary[monthName] = date.getDate();
}
return monthDaysDictionary;
}
getMonthsDaysForYear(2022);
Note: that month should be started with 1 as it is mentioned in this answer.
See my function and a test of it:
function numberOfDays(year, month) { // Reference: // https://arslankuyumculuk.com/how-to-calculate-leap-year-formula/ (2022-05-20 16:45 UTC)
numDays=0;
switch(month)
{
case 1:
numDays=31;
break;
case 2:
numDays=28;
break;
case 3:
numDays=31;
break;
case 4:
numDays=30;
break;
case 5:
numDays=31;
break;
case 6:
numDays=30;
break;
case 7:
numDays=31;
break;
case 8:
numDays=31;
break;
case 9:
numDays=30;
break;
case 10:
numDays=31;
break;
case 11:
numDays=30;
break;
case 12:
numDays=31;
break;
}
if(month==2)
{
if( (year % 100) == 0 )
{
if( (year % 400) == 0 )
{
numDays=29;
}
}
else
{
if( (year % 4) == 0 )
{
numDays=29;
}
}
}
//
return numDays;
}
// Test:
const years = [2019,2020,2021,2022,2023,2024,2025,2026,2027,2028,2100,2400];
month=2;
for (let i = 0; i < years.length; i++)
{
let text = "";
text += years[i] + '/' + month.toString() + ": " + numberOfDays(years[i], month).toString();
alert(text);
}
for (let m = 1; m <= 12; m++)
{
let text2 = "";
text2 += "2022/" + m.toString() + ": " + numberOfDays(2022, m).toString();
alert(text2);
}