How do I keep Python print from adding newlines or spaces?

In Python 3, use

print('h', end='')

to suppress the endline terminator, and

print('a', 'b', 'c', sep='')

to suppress the whitespace separator between items. See the documentation for print

import sys

sys.stdout.write('h')
sys.stdout.flush()

sys.stdout.write('m')
sys.stdout.flush()

You need to call sys.stdout.flush() because otherwise it will hold the text in a buffer and you won't see it.

Greg is right-- you can use sys.stdout.write

Perhaps, though, you should consider refactoring your algorithm to accumulate a list of <whatevers> and then

lst = ['h', 'm']
print  "".join(lst)

Or use a +, i.e.:

>>> print 'me'+'no'+'likee'+'spacees'+'pls'
menolikeespaceespls

Just make sure all are concatenate-able objects.

Python 2.5.2 (r252:60911, Sep 27 2008, 07:03:14)
[GCC 4.3.1] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> print "hello",; print "there"
hello there
>>> print "hello",; sys.stdout.softspace=False; print "there"
hellothere

But really, you should use sys.stdout.write directly.

For completeness, one other way is to clear the softspace value after performing the write.

import sys
print "hello",
sys.stdout.softspace=0
print "world",
print "!"

prints helloworld !

Using stdout.write() is probably more convenient for most cases though.

Regain control of your console! Simply:

from __past__ import printf

where __past__.py contains:

import sys
def printf(fmt, *varargs):
    sys.stdout.write(fmt % varargs)

then:

>>> printf("Hello, world!\n")
Hello, world!
>>> printf("%d %d %d\n", 0, 1, 42)
0 1 42
>>> printf('a'); printf('b'); printf('c'); printf('\n')
abc
>>>

Bonus extra: If you don't like print >> f, ..., you can extending this caper to fprintf(f, ...).