I think, java's documentation already explains why.
Here:Definite Assignment
For every access of a local variable or blank final field x, x must be definitely assigned before the access, or a compile-time error occurs.
And here:Initial Values of Variables
Every variable in a program must have a value before its value is used:
Each class variable, instance variable, or array component is initialized with a default value when it is created (§15.9, §15.10.2):
For type byte, the default value is zero, that is, the value of (byte)0.
For type short, the default value is zero, that is, the value of (short)0.
For type int, the default value is zero, that is, 0.
For type long, the default value is zero, that is, 0L.
For type float, the default value is positive zero, that is, 0.0f.
For type double, the default value is positive zero, that is, 0.0d.
For type char, the default value is the null character, that is, '\u0000'.
For type boolean, the default value is false.
For all reference types (§4.3), the default value is null.
And here:Creation of New Class Instances
If there is not sufficient space available to allocate memory for the object, then creation of the class instance completes abruptly with an OutOfMemoryError. Otherwise, all the instance variables in the new object, including those declared in superclasses, are initialized to their default values (§4.12.5).
so when you use Example1 e = new Example1(); the int a will be 0, but the local variable b still not definite assignment.