If we don’t have a number in ${desc}, we log out extId and if doesn’t have extId, then it goes with empty string.
I tried to convert this:
if (/^\d+$/.test(desc)) {
console.log(desc);
}
if (!/^\d+$/.test(desc) && exlId != null) {
console.log(extId);
} else {
console.log("");
}
to this :
/^\d+$/.test(desc)
? desc
: ""
? !/^\d+$/.test(desc) && extId != null
: ""
But this didn't work. What I do wrong?
If I got your question correctly:
const log = /^\d+$/.test(desc) ? desc : extId ? extId : "";
// Prints: -------------------------^-------------^-------^
or alternatively:
const log = /^\d+$/.test(desc) && desc || extId && extId || "";
PS: fix also your typo: exlId !== extId
Might be Your syntax is wrong to implement the multiple conditions in the ternary operator
It should be like
condition1 ? condition2 ? Expression1 : Expression2 : Expression3
/^\d+$/.test(desc)
? !/^\d+$/.test(desc) && extId != null ?
"" : desc;
check out this for more info https://www.geeksforgeeks.org/how-to-use-multiple-ternary-operators-in-a-single-statement-in-javascript/#:~:text=In%20the%20above%20syntax%2C%20we,then%20the%20output%20is%20Expression1.
Here's your ternary statement:
/^\d+$/.test(desc) ? desc : "" ? !/^\d+$/.test(desc) && extId != null : "";
The above statement if written in if-else form:
if (/^\d+$/.test(desc)) {
console.log(desc);
}
else if ("") {
console.log(!/^\d+$/.test(desc) && extId != null);
}
else {
console.log("");
}
You can see the issue here. Now here is the correct ternary statement:
/^\d+$/.test(desc) ? desc : extId ? extId : "";