Saving output in the same folder as the original script in Python

user19977266 0
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I run Run.py where I am calling File1.py which is located in another folder 1. How do I save the output of File1.py in 1.txt in the same folder in which it is located and not the folder in which Run.py is located?

Run.py is

import subprocess

print(subprocess.run(['python',rf'C:\\Users\\USER\\OneDrive - Technion\\Research_Technion\\Python_PNM\\Sept15_2022\\Test\\1\\File1.py']))

File.py is

import csv

A=1
B=2
C=A+B
print(C)

with open('1.txt', 'w') as f:
    writer = csv.writer(f)
    print(C)
    f.writelines('R'+ '\n')
    f.write(str(C))
subprocess python
2 Answers

You can find the path of the currently running script with the __file__ variable. So something like this would probably work:

import os

current_dir = os.path.dirname(__file__)
filename = os.path.join(current_dir, "1.txt")

with open(filename, "w") as f:
  # rest of code goes here
Jeanot Zubler0

Just concatenate the path where the file.py is located to that 1.txt. You can get the path where file.py is located by:

import os
file_py_path = os.path.dirname(os.path.realpath(__file__))

Explore os.path.join() to join paths, this way you will avoid problems related to diff filesystems.

xpeiro0
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