The Question Is to print if the entered number is Armstrong number or not In C?

An Armstrong number is a n digit number, which is equal to the sum of the nth powers of its digits. For example: 153 is an Armstrong number because the sum of it's digits raised to the n-th power is equal to the number itself --> 1^3 + 5^3 + 3^3 = 153.

int getNumberOfDigits(int number) {
    int counter = 0;
    while(number != 0)
    {
        counter++;
        number = number/10;
    }
    return counter;
}


void isArmstrong(int number)
{
    int digitsCount = getNumberOfDigits(number);
    int sum = 0, old_number = number; // saving the number in a variable so we can compare our answer to it
    while(number != 0) {
        sum += pow(number%10,digitsCount); // number%10 returns the last digit in the number
        number = number/10;
    }
    if(sum == old_number)
        printf("%d is an armstrong number",old_number);
    else
        printf("%d is not an armstrong number",old_number);
 
}