Please have a look at the snippet at the end of the post. I am essentially looking for a cleaner way to obtain the same result. I have a tibble where the x column is a character vector (I did not translate it into a factor, but this is actually what it is). Each factor appears multiple times and it always has an associated numerical value (the w column in the tibble). I would like to keep the top 4 factors according to the sum of their associated w values and change everything else into an "other" factor. I achieve it below, but I wonder if there is a smarter way to do the same using e.g. forcats.
Any suggestion is appreciated
library(tidyverse)
df <- tibble(x=rep(letters[1:10], 10), w=seq(100))
df
#> # A tibble: 100 × 2
#> x w
#> <chr> <int>
#> 1 a 1
#> 2 b 2
#> 3 c 3
#> 4 d 4
#> 5 e 5
#> 6 f 6
#> 7 g 7
#> 8 h 8
#> 9 i 9
#> 10 j 10
#> # … with 90 more rows
###detect the first 4 factors based on the w column
ff <- df |>
group_by(x) |>
summarise(w_tot=sum(w)) |>
ungroup() |>
arrange(desc(w_tot)) |>
slice(1:4) |>
pull(x)
ff
#> [1] "j" "i" "h" "g"
## recode the data
df_new <- df |>
mutate(w=if_else(x %in% ff, x, "other"))
df_new
#> # A tibble: 100 × 2
#> x w
#> <chr> <chr>
#> 1 a other
#> 2 b other
#> 3 c other
#> 4 d other
#> 5 e other
#> 6 f other
#> 7 g g
#> 8 h h
#> 9 i i
#> 10 j j
#> # … with 90 more rows
Created on 2022-09-16 by the reprex package (v2.0.1)