Smart design of a math parser?

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What is the smartest way to design a math parser? What I mean is a function that takes a math string (like: "2 + 3 / 2 + (2 * 5)") and returns the calculated value? I did write one in VB6 ages ago but it ended up being way to bloated and not very portable (or smart for that matter...). General ideas, psuedo code or real code is appreciated.

10 Answers

You have a couple of approaches. You could generate dynamic code and execute it in order to get the answer without needing to write much code. Just perform a search on runtime generated code in .NET and there are plenty of examples around.

Alternatively you could create an actual parser and generate a little parse tree that is then used to evaluate the expression. Again this is pretty simple for basic expressions. Check out codeplex as I believe they have a math parser on there. Or just look up BNF which will include examples. Any website introducing compiler concepts will include this as a basic example.

Codeplex Expression Evaluator

If you have an "always on" application, just post the math string to google and parse the result. Simple way but not sure if that's what you need - but smart in some way i guess.

Assuming your input is an infix expression in string format, you could convert it to postfix and, using a pair of stacks: an operator stack and an operand stack, work the solution from there. You can find general algorithm information at the Wikipedia link.

ANTLR is a very nice LL(*) parser generator. I recommend it highly.

11 years into the future from when this question was asked: If you don't want to re-invent the wheel, there are many exotic math parsers out there.

There is one that I wrote years ago which supports arithmetic operations, equation solving, differential calculus, integral calculus, basic statistics, function/formula definition, graphing, etc.

Its called ParserNG and its free.

Evaluating an expression is as simple as:

    MathExpression expr = new MathExpression("(34+32)-44/(8+9(3+2))-22"); 
    System.out.println("result: " + expr.solve());

    result: 43.16981132075472

Or using variables and calculating simple expressions:

 MathExpression expr = new MathExpression("r=3;P=2*pi*r;"); 
System.out.println("result: " + expr.getValue("P"));

Or using functions:

MathExpression expr = new MathExpression("f(x)=39*sin(x^2)+x^3*cos(x);f(3)"); 
System.out.println("result: " + expr.solve());

result: -10.65717648378352

Or to evaluate the derivative at a given point(Note it does symbolic differentiation(not numerical) behind the scenes, so the accuracy is not limited by the errors of numerical approximations):

MathExpression expr = new MathExpression("f(x)=x^3*ln(x); diff(f,3,1)"); 
System.out.println("result: " + expr.solve());

 result: 38.66253179403897

Which differentiates x^3 * ln(x) once at x=3. The number of times you can differentiate is 1 for now.

or for Numerical Integration:

MathExpression expr = new MathExpression("f(x)=2*x; intg(f,1,3)"); 
System.out.println("result: " + expr.solve());

result: 7.999999999998261... approx: 8

This parser is decently fast and has lots of other functionality.

Work has been concluded on porting it to Swift via bindings to Objective C and we have used it in graphing applications amongst other iterative use-cases.

DISCLAIMER: ParserNG is authored by me.

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