How do I write code in order to generate random numbers in a way that a random number can only be printed once every 5 times

Wasmot 0
Viewed 42

I've written code in python in order to generate random numbers between 110-115, 19 times. The code works however I would like to add code that states that the same random numbers cannot be printed out next to each other, they can only be printed out after the other 5 numbers have been used. for example:

[112, 113, 115, 110, 111, 114, 112, 113, 115, 110, 111, 114...]

until 19 values have been printed.

I have the following code:

randomlist = []

for i in range(19):
    
    n = random.randint(110,115)
    randomlist.append(n)

print(*randomlist, sep = "\n")
python-3.x python
2 Answers

Try this, to generate 19 nos where no repetition in 5 consecutive nos.

import random
randomlist = []
while len(randomlist) < 19:
    n = random.randint(110,115)
    if n not in randomlist[-5:]:
        randomlist.append(n)
    else:
        continue

Hope this helps...

Sachin Kohli0

Try this below code , it will solve your problem.

import random
randomlist = []
i = 0
number_of_values = 19

while len(randomlist) < number_of_values:
    n = random.randint(110,115)
    if n not in randomlist[-5:]:
        randomlist.append(n)
print(randomlist, sep = "\n")
sujith kumar0
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