Cannot get output for more than one user defined digit

quartz6.626 0
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def main():

Need the code to ask the user a number and print out number in words digit by digit. Ex. Input: 473 Output: four seven three

numbers = ["zero","one","two","three","four","five","six","seven","eight","nine"]

n = eval(input('Please input a number: '))
print('You typed a number: ',n)
print('The number in words: ', numbers[n])

Cannot get code here to print out more than one digit. I have tried a few for loops and always get the error message with my index

main()

list indexing input python
4 Answers

Because your list has 10 items and it can not find index for example 324 so you should split your number into digits and try it for each digit.

numbers = ["zero","one","two","three","four","five","six","seven","eight","nine"]

n = int(input('Please input a number: '))
print('You typed a number: ',n)
print('The number in words: ', end="")
for char in str(n):
    print(numbers[int(char)], end=" ")
print()
Arsham Mohammadi0

You are basically trying to access an eleent in an array(your array only have 10 elements, so works fine for n<=10) that doesn't exist. You need to extract the digits, and try for every digit.

Priyankar Koley0

you can put numbers in a dictionary numbers = {'0': 'zero', '1': 'one', '2': 'two', etc...}

then loop throw the user's string:

for number in n: print(numbers[number] + " ", end='')

Jed Ben nasr0

here is version that uses a list comprehension:

numbers = ["zero","one","two","three","four","five","six","seven","eight","nine"]
inp = input()
print(" ".join([numbers[int(dig)] for dig in inp]))
lroth0
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