Matplotlib explicit value to colormap

meow 0
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Matplotlib does not support any simple way to define an explicit color map of the form:

my_map = {
    1: "green",
    2: "orange",
    3: "red"
}

I would have to use a custom colormap with normalization that just so happens to fall onto number 1, 2, 3 (which seems like way too complicated for something so simple...), right?

The only really simple approach I found was to use cmap = ListedColormap(['green', 'orange', 'red'], 'indexed'), which, however, will obviously break if not all numbers occur at least once, e.g. assuming the categorical data I want to plot comes as data = [2,2,2,2,2], but all will be mapped to green instead of orange.

matplotlib python
1 Answers

As you say, this works:

from matplotlib.colors import ListedColormap
import matplotlib.pyplot as plt
import numpy as np

cmap = ListedColormap(['green', 'orange', 'red'], 'indexed')
data = np.random.randint(1, 4, size=(5, 5))
plt.imshow(data, cmap=cmap)
plt.colorbar()

And produces:

Output when all values present

But if you only have ones (say), the colourmap scales automatically. You could fix it with vmin and vmax:

data = np.ones((5, 5))
plt.imshow(data, cmap=cmap, vmin=1, vmax=3)
plt.colorbar()

It gives you:

The expected output

Which I think is the required output.

kwinkunks0
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