How to split and trim a sting with groovy in one line

ofirule 0
Viewed 53

I have a string with values sperated by the , char. e.g:

vals_str = "a, b ,    55,  val444"

and I would like to generate the following array:

vals_arr = ["a", "b", "55", "val444"]

How can I do it with groovy in one line?

groovy
5 Answers

You could also use a findAll() approach here:

vals_str = "a, b ,    55,  val444"
vals_arr = vals_str.findAll("[^,\\s]+")
println vals_arr  // [a, b, 55, val444]
Tim Biegeleisen0

String.split could accept regex

def vals_str = "a, b ,    55,  val444"
def vals_arr = vals_str.split(/\s*,\s*/)
daggett0

Inspired by link

I was able to achieve the wanted solution in two ways:

1.

vals_str = "a, b ,    55,  val444"
vals_arr = vals_str.split(",").collect{ it.trim() }

vals_str = "a, b ,    55,  val444"
vals_arr = vals_str.split(",")*.trim()
ofirule0

You could use String tokenize() (source)

assert "a, b ,    55,  val444".tokenize(", ") == ["a", "b", "55", "val444"]
aspok0

Regex is the way to go:

String res = "a, b ,    55,  val444".split( /\W+/ )
assert res.toString() == '[a, b, 55, val444]'
injecteer0
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