Split string to only get positions 1, 2 and 3, removing everything else

LautaroColella 0
Viewed 35

I am using nodejs + mysql, and I want to show a date in a json api.

The date is not a string, is a mysql date type.

E* I can't select date(columnname) because I am already selecting everything from the table. This is my query:

var query_ = `
SELECT p.*, GROUP_CONCAT(ss.name) AS technologies 
FROM Projects_Project AS p
JOIN Projects_rel_Project_Skill AS prps ON prps.Project = p.ProjectID
JOIN Skills AS ss ON ss.skillID = prps.Skill
GROUP BY p.ProjectID
ORDER BY p.date DESC;`;

var mylist = results.map(row => ({
    'date': row.date
}));

This will output: "2022-08-24T05:00:00.000Z"

So my attempt was to use .split after the T, but it gives an error saying that .split can only be used to strings and date is not a string.

var mylist = results.map(row => ({
    'date': row.date.split('T')[0]
}));

So searching more I attempt to convert it to string, but the output is different.

var mylist = results.map(row => ({
    'date': row.date.toString()
}));

"Wed Aug 24 2022 00:00:00 GMT-0500 (Central Daylight Time)"

So now the problem is that I only want "Aug 24 2022" and I don't know how to do it. Using .split(' ')[1] will only give me "Aug"

I also attempt to do .split(' ')[1, 2, 3] and .split(' ')[1][2][3] but nothing.

mysql json arrays javascript
3 Answers

you need to slice your splitted date

wantedDate = .split(' ').slice(1, 3)

then you can join your wantedDate to get the string date

islemdev0
elclanrs0

row.date is a Date object, you can convert it into string with toISOString() method:

const now = new Date();
console.log(now.toISOString().split("T"))

So in your case it would be:

var mylist = results.map(row => ({
    'date': row.date.toISOString().split('T')[0]
}));
vanowm0
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