Pharo dictionary

Mansour Faouziel 0
Viewed 27

I have an issue and this is the result when i call one method in my code.

t do:[:i |
        dict := Dictionary newFrom:{t->items}.
    ].

t is an

OrderedCollection(#name #lastName #birthDate)

and items too. items an OrderedCollection('cs0yh1n1b2bm0wps16uvy7tfi' 'cs0yh1k1t3bgdszfupe407qdg' 21 April 1975)

a Dictionary [1 item] (an OrderedCollection(#name #lastName #birthDate)->an OrderedCollection('cs0yh1n1b2bm0wps16uvy7tfi' 'cs0yh1k1t3bgdszfupe407qdg' 21 April 1975).

I would like to obtain a gender dictionary

a Dictionary (#name->'cs0yh1n1b2bm0wps16uvy7tfi' #lastNamename->'cs0yh1k1t3bgdszfupe407qdg' #birthDay->21 April 1975)

how can i do this please ?

pharo smalltalk
1 Answers

You are creating a new Dictionary each time through the loop. You need to create a new (empty) Dictionary before the loop and add each element using #'at:put:'. If you want to map index 1 in t to index 1 in items, then you need to have a counter. Perhaps 1 to: t size do: [:i | ...].

You are asking a lot of questions about Smalltalk and we are delighted to have you learning it. Have you tried spending a few hours studying a book or taking a course? I recommend the Pharo Mooc, some Pharo books, or some Smalltalk books.

James Foster0
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