List: Find the first index and count the occurrence of a specific list in list of lists

yadavender yadav 0
Viewed 38

we have a variable named location.

location=[["world", 'Live'], ["alpha",'Live'], ['hello', 'Scheduled'],['alpha', 'Live'], ['just', 'Live'], ['alpha','Scheduled'], ['alpha', 'Live']]

i want to find the first index and count occurrence of list["alpha",'Live'] in location. i tried the following:

index= [location.index(i) for i in location if i ==["alpha", 'Live'] ]
count = [location.count(i) for i in location if i ==["alpha",'Live'] ]
print('index',index)
print('count', count)

this returns: index [1, 1, 1] count [3, 3, 3]

but is there a way to find both first index, count simultaneously using list comprehension.

expected output:

index, count = 1, 3

list-comprehension list python-3.x python
1 Answers

does this solve you problem?

location=[["world", 'Live'], ["alpha",'Live'], ['hello', 'Scheduled'],['alpha', 'Live'], ['just', 'Live'], ['alpha','Scheduled'], ['alpha', 'Live']]
index= location.index(["alpha",'Live'])
count = location.count(["alpha",'Live'])
print('index',index)
print('count', count)

if ['alpha','live'] is not found, find the first ['alpha',??] and print its index and count.

location = [["world", 'Live'], ["alpha", 'Live'], ['hello', 'Scheduled'], [
    'alpha', 'Live'], ['just', 'Live'], ['alpha', 'Scheduled'], ['alpha', 'Live']]

key = ["alpha", 'Lsive']

count = location.count(key)

if count:
    index = location.index(key)
    print('count', count)
    print('index', index)
else:
    for i in location:
        if i[0] == key[0]:
            key = i
            count = location.count(key)
            index = location.index(key)
            print('count', count)
            print('index', index)
    else:
        print('not found')

cleaner code by @yadavender yadav

location = [["alpha", 'Scheduled'], ["alpha", 'Live'], ['hello', 'Scheduled'], [
    'alpha', 'Live'], ['just', 'Live'], ['alpha', 'Scheduled'], ['alpha', 'Live']]

key = ["alpha", 'Scheduled']

count = location.count(key)

if count:
    index = location.index(key)
else:
    index=[location.index(i) for i in location if i[0]=="alpha"][0]
print('count', count)
print('index', index)
Hannon qaoud0
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