Without local access to the server, is there any way to duplicate/clone a MySQL db (with content and without content) into another without using mysqldump?
I am currently using MySQL 4.0.
Without local access to the server, is there any way to duplicate/clone a MySQL db (with content and without content) into another without using mysqldump?
I am currently using MySQL 4.0.
You can duplicate a table without data by running:
CREATE TABLE x LIKE y;
(See the MySQL CREATE TABLE Docs)
You could write a script that takes the output from SHOW TABLES from one database and copies the schema to another. You should be able to reference schema+table names like:
CREATE TABLE x LIKE other_db.y;
As far as the data goes, you can also do it in MySQL, but it's not necessarily fast. After you've created the references, you can run the following to copy the data:
INSERT INTO x SELECT * FROM other_db.y;
If you're using MyISAM, you're better off to copy the table files; it'll be much faster. You should be able to do the same if you're using INNODB with per table table spaces.
If you do end up doing an INSERT INTO SELECT, be sure to temporarily turn off indexes with ALTER TABLE x DISABLE KEYS!
EDIT Maatkit also has some scripts that may be helpful for syncing data. It may not be faster, but you could probably run their syncing scripts on live data without much locking.
If you are using Linux, you can use this bash script: (it perhaps needs some additional code cleaning but it works ... and it's much faster then mysqldump|mysql)
#!/bin/bash
DBUSER=user
DBPASSWORD=pwd
DBSNAME=sourceDb
DBNAME=destinationDb
DBSERVER=db.example.com
fCreateTable=""
fInsertData=""
echo "Copying database ... (may take a while ...)"
DBCONN="-h ${DBSERVER} -u ${DBUSER} --password=${DBPASSWORD}"
echo "DROP DATABASE IF EXISTS ${DBNAME}" | mysql ${DBCONN}
echo "CREATE DATABASE ${DBNAME}" | mysql ${DBCONN}
for TABLE in `echo "SHOW TABLES" | mysql $DBCONN $DBSNAME | tail -n +2`; do
createTable=`echo "SHOW CREATE TABLE ${TABLE}"|mysql -B -r $DBCONN $DBSNAME|tail -n +2|cut -f 2-`
fCreateTable="${fCreateTable} ; ${createTable}"
insertData="INSERT INTO ${DBNAME}.${TABLE} SELECT * FROM ${DBSNAME}.${TABLE}"
fInsertData="${fInsertData} ; ${insertData}"
done;
echo "$fCreateTable ; $fInsertData" | mysql $DBCONN $DBNAME
All of the prior solutions get at the point a little, however, they just don't copy everything over. I created a PHP function (albeit somewhat lengthy) that copies everything including tables, foreign keys, data, views, procedures, functions, triggers, and events. Here is the code:
/* This function takes the database connection, an existing database, and the new database and duplicates everything in the new database. */
function copyDatabase($c, $oldDB, $newDB) {
// creates the schema if it does not exist
$schema = "CREATE SCHEMA IF NOT EXISTS {$newDB};";
mysqli_query($c, $schema);
// selects the new schema
mysqli_select_db($c, $newDB);
// gets all tables in the old schema
$tables = "SELECT table_name
FROM information_schema.tables
WHERE table_schema = '{$oldDB}'
AND table_type = 'BASE TABLE'";
$results = mysqli_query($c, $tables);
// checks if any tables were returned and recreates them in the new schema, adds the foreign keys, and inserts the associated data
if (mysqli_num_rows($results) > 0) {
// recreates all tables first
while ($row = mysqli_fetch_array($results)) {
$table = "CREATE TABLE {$newDB}.{$row[0]} LIKE {$oldDB}.{$row[0]}";
mysqli_query($c, $table);
}
// resets the results to loop through again
mysqli_data_seek($results, 0);
// loops through each table to add foreign key and insert data
while ($row = mysqli_fetch_array($results)) {
// inserts the data into each table
$data = "INSERT IGNORE INTO {$newDB}.{$row[0]} SELECT * FROM {$oldDB}.{$row[0]}";
mysqli_query($c, $data);
// gets all foreign keys for a particular table in the old schema
$fks = "SELECT constraint_name, column_name, table_name, referenced_table_name, referenced_column_name
FROM information_schema.key_column_usage
WHERE referenced_table_name IS NOT NULL
AND table_schema = '{$oldDB}'
AND table_name = '{$row[0]}'";
$fkResults = mysqli_query($c, $fks);
// checks if any foreign keys were returned and recreates them in the new schema
// Note: ON UPDATE and ON DELETE are not pulled from the original so you would have to change this to your liking
if (mysqli_num_rows($fkResults) > 0) {
while ($fkRow = mysqli_fetch_array($fkResults)) {
$fkQuery = "ALTER TABLE {$newDB}.{$row[0]}
ADD CONSTRAINT {$fkRow[0]}
FOREIGN KEY ({$fkRow[1]}) REFERENCES {$newDB}.{$fkRow[3]}({$fkRow[1]})
ON UPDATE CASCADE
ON DELETE CASCADE;";
mysqli_query($c, $fkQuery);
}
}
}
}
// gets all views in the old schema
$views = "SHOW FULL TABLES IN {$oldDB} WHERE table_type LIKE 'VIEW'";
$results = mysqli_query($c, $views);
// checks if any views were returned and recreates them in the new schema
if (mysqli_num_rows($results) > 0) {
while ($row = mysqli_fetch_array($results)) {
$view = "SHOW CREATE VIEW {$oldDB}.{$row[0]}";
$viewResults = mysqli_query($c, $view);
$viewRow = mysqli_fetch_array($viewResults);
mysqli_query($c, preg_replace("/CREATE(.*?)VIEW/", "CREATE VIEW", str_replace($oldDB, $newDB, $viewRow[1])));
}
}
// gets all triggers in the old schema
$triggers = "SELECT trigger_name, action_timing, event_manipulation, event_object_table, created
FROM information_schema.triggers
WHERE trigger_schema = '{$oldDB}'";
$results = mysqli_query($c, $triggers);
// checks if any triggers were returned and recreates them in the new schema
if (mysqli_num_rows($results) > 0) {
while ($row = mysqli_fetch_array($results)) {
$trigger = "SHOW CREATE TRIGGER {$oldDB}.{$row[0]}";
$triggerResults = mysqli_query($c, $trigger);
$triggerRow = mysqli_fetch_array($triggerResults);
mysqli_query($c, str_replace($oldDB, $newDB, $triggerRow[2]));
}
}
// gets all procedures in the old schema
$procedures = "SHOW PROCEDURE STATUS WHERE db = '{$oldDB}'";
$results = mysqli_query($c, $procedures);
// checks if any procedures were returned and recreates them in the new schema
if (mysqli_num_rows($results) > 0) {
while ($row = mysqli_fetch_array($results)) {
$procedure = "SHOW CREATE PROCEDURE {$oldDB}.{$row[1]}";
$procedureResults = mysqli_query($c, $procedure);
$procedureRow = mysqli_fetch_array($procedureResults);
mysqli_query($c, str_replace($oldDB, $newDB, $procedureRow[2]));
}
}
// gets all functions in the old schema
$functions = "SHOW FUNCTION STATUS WHERE db = '{$oldDB}'";
$results = mysqli_query($c, $functions);
// checks if any functions were returned and recreates them in the new schema
if (mysqli_num_rows($results) > 0) {
while ($row = mysqli_fetch_array($results)) {
$function = "SHOW CREATE FUNCTION {$oldDB}.{$row[1]}";
$functionResults = mysqli_query($c, $function);
$functionRow = mysqli_fetch_array($functionResults);
mysqli_query($c, str_replace($oldDB, $newDB, $functionRow[2]));
}
}
// selects the old schema (a must for copying events)
mysqli_select_db($c, $oldDB);
// gets all events in the old schema
$query = "SHOW EVENTS
WHERE db = '{$oldDB}';";
$results = mysqli_query($c, $query);
// selects the new schema again
mysqli_select_db($c, $newDB);
// checks if any events were returned and recreates them in the new schema
if (mysqli_num_rows($results) > 0) {
while ($row = mysqli_fetch_array($results)) {
$event = "SHOW CREATE EVENT {$oldDB}.{$row[1]}";
$eventResults = mysqli_query($c, $event);
$eventRow = mysqli_fetch_array($eventResults);
mysqli_query($c, str_replace($oldDB, $newDB, $eventRow[3]));
}
}
}
Actually i wanted to achieve exactly that in PHP but none of the answers here were very helpful so here's my – pretty straightforward – solution using MySQLi:
// Database variables
$DB_HOST = 'localhost';
$DB_USER = 'root';
$DB_PASS = '1234';
$DB_SRC = 'existing_db';
$DB_DST = 'newly_created_db';
// MYSQL Connect
$mysqli = new mysqli( $DB_HOST, $DB_USER, $DB_PASS ) or die( $mysqli->error );
// Create destination database
$mysqli->query( "CREATE DATABASE $DB_DST" ) or die( $mysqli->error );
// Iterate through tables of source database
$tables = $mysqli->query( "SHOW TABLES FROM $DB_SRC" ) or die( $mysqli->error );
while( $table = $tables->fetch_array() ): $TABLE = $table[0];
// Copy table and contents in destination database
$mysqli->query( "CREATE TABLE $DB_DST.$TABLE LIKE $DB_SRC.$TABLE" ) or die( $mysqli->error );
$mysqli->query( "INSERT INTO $DB_DST.$TABLE SELECT * FROM $DB_SRC.$TABLE" ) or die( $mysqli->error );
endwhile;
an SQL that shows SQL commands, need to run to duplicate a database from one database to another. for each table there is create a table statement and an insert statement. it assumes both databases are on the same server:
select @fromdb:="crm";
select @todb:="crmen";
SET group_concat_max_len=100000000;
SELECT GROUP_CONCAT( concat("CREATE TABLE `",@todb,"`.`",table_name,"` LIKE `",@fromdb,"`.`",table_name,"`;\n",
"INSERT INTO `",@todb,"`.`",table_name,"` SELECT * FROM `",@fromdb,"`.`",table_name,"`;")
SEPARATOR '\n\n')
as sqlstatement
FROM information_schema.tables where table_schema=@fromdb and TABLE_TYPE='BASE TABLE';
Mysqldump isn't bad solution. Simplest way to duplicate database:
mysqldump -uusername -ppass dbname1 | mysql -uusername -ppass dbname2
Also, you can change storage engine by this way:
mysqldump -uusername -ppass dbname1 | sed 's/InnoDB/RocksDB/' | mysql -uusername -ppass dbname2